The IUPAC name of the product that formed in the following chemical reaction is: Acetone $\xrightarrow{\text{(i) } C_2H_5MgBr, \text{ dry Ether}}$ $\xrightarrow{\text{(ii) } H_2O, H^+}$ Product

The reaction involves the nucleophilic addition of a Grignard reagent to a ketone:

1. Reactants: Acetone is Propan-2-one ($CH_3-CO-CH_3$). The Grignard reagent is Ethyl magnesium bromide ($C_2H_5MgBr$).
2. Mechanism: The ethyl group ($C_2H_5^-$) from the Grignard reagent attacks the carbonyl carbon of acetone. The oxygen coordinates with $MgBr$. This forms an intermediate adduct. $(CH_3)_2C=O + C_2H_5MgBr \rightarrow (CH_3)_2C(OMgBr)(C_2H_5)$
3. Hydrolysis: Acid hydrolysis ($H_2O/H^+$) converts the adduct into a tertiary alcohol. $(CH_3)_2C(OMgBr)(C_2H_5) + H_2O \rightarrow (CH_3)_2C(OH)(C_2H_5) + Mg(OH)Br$
4. Product Identification: The structure formed is $CH_3-C(OH)(CH_3)-CH_2-CH_3$. The longest carbon chain containing the -OH group has 4 carbons (Butane). The substituent is a methyl group at position 2, and the hydroxyl group is also at position 2. IUPAC Name: 2-Methylbutan-2-ol.