What is the correct electronic configuration of the central atom in $K_4[Fe(CN)_6]$ based on crystal field the

Question

What is the correct electronic configuration of the central atom in $K_4[Fe(CN)_6]$ based on crystal field theory?

Accepted Answer

For $K_4[Fe(CN)_6]$, the oxidation state of Fe is +2. The ground state of $Fe^{2+}$ is $[Ar]3d^6 4s^0$. In the presence of a strong field ligand like $CN^-$, the electrons pair up in the $t_{2g}$ orbitals, resulting in a configuration of $t_{2g}^6 e_g^0$.

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