A 800 turn coil of effective area $0.05 ext{ m}^2$ is kept perpendicular to a magnetic field $5 imes 10^{-

Question

A 800 turn coil of effective area $0.05 	ext{ m}^2$ is kept perpendicular to a magnetic field $5 	imes 10^{-5} 	ext{ T}$. When the plane of the coil is rotated by $90^\circ$ around any of its coplanar axis in $0.1 	ext{ s}$, the emf induced in the coil will be:

Accepted Answer

Magnetic field $B = 5 	imes 10^{-5} 	ext{ T}$. Number of turns in coil $N = 800$. Area of coil $A = 0.05 	ext{ m}^2$. Time taken to rotate $\Delta t = 0.1 	ext{ s}$. Initial angle $	heta_1 = 0^\circ$. Final angle $	heta_2 = 90^\circ$. Change in magnetic flux $\Delta \phi = NBA \cos 90^\circ - BA \cos 0^\circ = -NBA = -800 	imes 5 	imes 10^{-5} 	imes 0.05 = -2 	imes 10^{-3} 	ext{ weber}$. $e = -\frac{\Delta \phi}{\Delta t} = -\frac{-2 	imes 10^{-3} 	ext{ Wb}}{0.1 	ext{ s}} = 0.02 	ext{ V}$.

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