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NEET PHYSICSMOTION IN A STRAIGHT LINEMedium

Question

A body dropped from a height hh with an initial speed of zero, strikes the ground with a velocity 3 km/h3 \text{ km/h}. Another body of the same mass is dropped from the same height hh with an initial speed u=4 km/hu' = 4 \text{ km/h}. Find the final velocity of the second body with which it strikes the ground.

A

3 km/h

B

4 km/h

C

5 km/h

D

12 km/h

Step-by-Step Solution

  1. Analyze First Body: The body falls from height hh starting from rest (u1=0u_1 = 0).
  • Using the kinematic equation v2=u2+2asv^2 = u^2 + 2as with a=ga=g and s=hs=h: v12=u12+2ghv_1^2 = u_1^2 + 2gh (3)2=02+2gh    2gh=9(3)^2 = 0^2 + 2gh \implies 2gh = 9
  1. Analyze Second Body: The second body falls from the same height hh but with an initial velocity u2=4 km/hu_2 = 4 \text{ km/h}. The mass of the body does not affect the final velocity in free fall (neglecting air resistance).
  • Using the same kinematic equation for the final velocity v2v_2: v22=u22+2ghv_2^2 = u_2^2 + 2gh
  • Substitute the known values (u2=4u_2 = 4 and 2gh=92gh = 9): v22=(4)2+9v_2^2 = (4)^2 + 9 v22=16+9=25v_2^2 = 16 + 9 = 25 v2=25=5 km/hv_2 = \sqrt{25} = 5 \text{ km/h} .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEdroppedheightinitialstrikesground

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