back to directory
NEET PHYSICSGeneralMedium

Question

A bullet from a gun is fired on a rectangular wooden block with velocity uu. When bullet travels 2424 cm through the block along its length horizontally, velocity of bullet becomes u3\frac{u}{3}. Then it further penetrates into the block in the same direction before coming to rest exactly at the other end of the block. The total length of the block is

A

27 cm

B

24 cm

C

28 cm

D

30 cm

Step-by-Step Solution

Using v2=u2+2asv^2 = u^2 + 2as, for the first part: (u3)2=u2+2a(24)    8u29=48a    a=u254(\frac{u}{3})^2 = u^2 + 2a(24) \implies -\frac{8u^2}{9} = 48a \implies a = -\frac{u^2}{54}. For the second part, let the remaining distance be xx: 02=(u3)2+2ax    0=u29+2(u254)x    u29=u227x    x=30^2 = (\frac{u}{3})^2 + 2ax \implies 0 = \frac{u^2}{9} + 2(-\frac{u^2}{54})x \implies \frac{u^2}{9} = \frac{u^2}{27}x \implies x = 3 cm. Total length = 24+3=2724 + 3 = 27 cm.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSbulletrectangularwoodenvelocitybullet

More PHYSICS Questions

View all

A capacitor of capacitance $C = 900 \text{ pF}$ is charged fully by $100 \text{ V}$ battery $B$ as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance $C = 900 \text{ pF}$ as shown in figure (b). The electrostatic energy stored by the system (b) is

A.$4.5 \times 10^{-6} \text{ J}$
B.$3.25 \times 10^{-6} \text{ J}$
C.$2.25 \times 10^{-6} \text{ J}$
D.$1.5 \times 10^{-6} \text{ J}$
MediumSolve

Two identical charged spheres suspended from a common point by two massless strings of lengths l are initially at a distance d (d << l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as:

A.v ∝ x
B.v ∝ x⁻¹/²
C.v ∝ x⁻¹
D.v ∝ x¹/²
HardSolve

A block A of mass $m_1$ rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of the table and from its other end, another block B of mass $m_2$ is suspended. The coefficient of kinetic friction between block A and the table is $\mu_k$. When block A is sliding on the table, the tension in the string is:

A.$\frac{(m_2 + \mu_k m_1)g}{(m_1 + m_2)}$
B.$\frac{(m_2 - \mu_k m_1)g}{(m_1 + m_2)}$
C.$\frac{m_1 m_2 (1 - \mu_k)g}{(m_1 + m_2)}$
D.$\frac{m_1 m_2 (1 + \mu_k)g}{(m_1 + m_2)}$
MediumSolve

A ball is thrown vertically upwards. Which of the following plots represents the speed-time graph of the ball during its height if the air resistance is not ignored?

A.Option 1
B.Option 2
C.4
D.Option 4
MediumSolve

A big circular coil of 1000 turns and average radius 10 m is rotating about its horizontal diameter at 2 rad s$^{-1}$. If the vertical component of earth's magnetic field at that place is $2 \times 10^{-5}$ T and electrical resistance of the coil is 12.56 $\Omega$, then the maximum induced current in the coil will be

A.0.25 A
B.1.5 A
C.1 A
D.2 A
HardSolve

A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd second?

A.7/5
B.5/7
C.7/3
D.3/7
EasySolve

The velocity of a bullet is reduced from $200 \text{ m/s}$ to $100 \text{ m/s}$ while travelling through a wooden block of thickness $10 \text{ cm}$. The retardation, assuming it to be uniform, will be:

A.$10 \times 10^4 \text{ m/s}^2$
B.$12 \times 10^4 \text{ m/s}^2$
C.$13.5 \times 10^4 \text{ m/s}^2$
D.$15 \times 10^4 \text{ m/s}^2$
MediumSolve

A body A starts from rest with an acceleration $a_1$. After $2$ seconds, another body B starts from rest with an acceleration $a_2$. If they travel equal distances in the $5^{\text{th}}$ second, after the start of A, then the ratio $a_1 : a_2$ is equal to:

A.5 : 9
B.5 : 7
C.9 : 5
D.9 : 7
MediumSolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →