A bullet is fired from a gun at the speed of $280 ext{ m s}^{-1}$ in the direction $30^\circ$ above the hori

Question

A bullet is fired from a gun at the speed of $280 	ext{ m s}^{-1}$ in the direction $30^\circ$ above the horizontal. The maximum height attained by the bullet is ($g = 9.8 	ext{ m s}^{-2}$, $\sin 30^\circ = 0.5$)

Accepted Answer

The maximum height $H$ is given by $H = \frac{u^2 \sin^2 	heta}{2g}$. Substituting the values: $H = \frac{(280)^2 	imes (\sin 30^\circ)^2}{2 	imes 9.8} = \frac{78400 	imes 0.25}{19.6} = \frac{19600}{19.6} = 1000 	ext{ m}$.

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