A radioactive nucleus ${}_Z^A X$ undergoes spontaneous decay in the sequence ${}_Z^A X o {}_{Z-1} B o {}_{

Question

A radioactive nucleus ${}_Z^A X$ undergoes spontaneous decay in the sequence ${}_Z^A X 	o {}_{Z-1} B 	o {}_{Z-3} C 	o {}_{Z-2} D$, where $Z$ is the atomic number of element $X$. The possible decay particles in the sequence are

Accepted Answer

On $\beta^+$ decay atomic number decreases by 1. On $\beta^-$ decay atomic number increases by 1. On $\alpha$ decay atomic number decreases by 2. The sequence is ${}_Z^A X \xrightarrow{\beta^+ 	ext{ decay}} {}_{Z-1} B \xrightarrow{\alpha 	ext{ decay}} {}_{Z-3} C \xrightarrow{\beta^- 	ext{ decay}} {}_{Z-2} D$. Hence correct order of decay are $\beta^+, \alpha, \beta^-$.

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