A screw gauge gives the following readings when used to measure the diameter of a wire. Main scale reading : 0

Question

A screw gauge gives the following readings when used to measure the diameter of a wire. Main scale reading : 0 mm. Circular scale reading : 52 divisions. Given that 1 mm on main scale corresponds to 100 divisions on the circular scale. The diameter of the wire from the above data is

Accepted Answer

Here, pitch of the screw gauge, $P = 1$ mm. Number of circular division, $n = 100$. Thus least count $LC = \frac{P}{n} = \frac{1}{100} = 0.01$ mm = $0.001$ cm. So, diameter of the wire = $MSR + (CSR 	imes LC) = 0 + (52 	imes 0.001$ cm) = $0.052$ cm.

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