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NEET PHYSICSALTERNATING CURRENTEasy

Question

A small-signal voltage V(t)=V0sin(ωt)V(t) = V_0 \sin(\omega t) is applied across an ideal capacitor C:

A

over a full cycle, the capacitor C does not consume any energy from the voltage source

B

current I(t) is in phase with voltage V(t)

C

current I(t) leads voltage V(t) by 180°

D

current I(t) lags voltage V(t) by 90°

Step-by-Step Solution

In an AC circuit containing only an ideal capacitor, the current I(t)I(t) leads the voltage V(t)V(t) by a phase angle of π/2\pi/2 or 9090^\circ . This eliminates options suggesting they are in phase, lead by 180°, or lag. The average power consumed over a full cycle is P=VrmsIrmscosϕP = V_{rms}I_{rms} \cos \phi. Since the phase difference ϕ=90\phi = 90^\circ, the power factor cosϕ=0\cos \phi = 0, meaning the average power consumed is zero. The capacitor stores energy during one part of the cycle and returns it to the source in the next.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ALTERNATING CURRENT. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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