A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is susp

Question

A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is

Accepted Answer

For a spring, $F = kx$. $10 = k \cdot 0.05$, so $k = \frac{10}{0.05} = 200 	ext{ N/m}$. Time period $T = 2\pi \sqrt{\frac{m}{k}} = 2\pi \sqrt{\frac{2}{200}} = 2\pi \sqrt{\frac{1}{100}} = 2\pi \cdot \frac{1}{10} = \frac{2 \cdot 3.14}{10} = 0.628 	ext{ s}$.

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