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NEET PHYSICSGeneralMedium

Question

A uniform conducting wire of length 12a12a and resistance 'RR' is wound up as a current carrying coil in the shape of, (i) an equilateral triangle of side 'aa'. (ii) a square of side 'aa'. The magnetic dipole moments of the coil in each case respectively are

A

3Ia2\sqrt{3} \, Ia^2 and 3Ia23 \, Ia^2

B

3Ia23 \, Ia^2 and Ia2Ia^2

C

3Ia23 \, Ia^2 and 4Ia24 \, Ia^2

D

4Ia24 \, Ia^2 and 3Ia23 \, Ia^2

Step-by-Step Solution

Current in the loop will be I=V/RI = V/R which is same for both loops. Magnetic moment of Triangle loop = NIANIA. M1=(12a3a)I34a2=3Ia2M_1 = (\frac{12a}{3a}) \cdot I \cdot \frac{\sqrt{3}}{4} a^2 = \sqrt{3}Ia^2. Magnetic moment of square loop = NIA=(12a4a)Ia2=3Ia2N'IA' = (\frac{12a}{4a}) \cdot I \cdot a^2 = 3Ia^2.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSuniformconductinglengthresistancecurrent

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