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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

A vehicle travels half the distance with speed vv and the remaining distance with speed 2v2v. Its average speed is:

A

\frac{3v}{4}

B

\frac{v}{3}

C

\frac{2v}{3}

D

\frac{4v}{3}

Step-by-Step Solution

  1. Define Average Speed: Average speed is defined as the ratio of the total distance traveled to the total time taken . vavg=Total DistanceTotal Timev_{avg} = \frac{\text{Total Distance}}{\text{Total Time}}
  2. Set Up Variables: Let the total distance be 2d2d. The vehicle travels the first half distance (dd) with speed v1=vv_1 = v and the second half distance (dd) with speed v2=2vv_2 = 2v.
  3. Calculate Time Intervals: Time for the first half (t1t_1) = distancespeed=dv\frac{\text{distance}}{\text{speed}} = \frac{d}{v} Time for the second half (t2t_2) = d2v\frac{d}{2v}
  4. Calculate Total Time: T=t1+t2=dv+d2v=2d+d2v=3d2vT = t_1 + t_2 = \frac{d}{v} + \frac{d}{2v} = \frac{2d + d}{2v} = \frac{3d}{2v}
  5. Calculate Average Speed: vavg=2d3d2v=2d×2v3d=4v3v_{avg} = \frac{2d}{\frac{3d}{2v}} = \frac{2d \times 2v}{3d} = \frac{4v}{3} Alternative Formula: For equal distances covered at speeds v1v_1 and v2v_2, the average speed is the harmonic mean: vavg=2v1v2v1+v2=2(v)(2v)v+2v=4v23v=4v3v_{avg} = \frac{2v_1v_2}{v_1 + v_2} = \frac{2(v)(2v)}{v + 2v} = \frac{4v^2}{3v} = \frac{4v}{3}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEvehicletravelsdistanceremainingdistance

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