An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are b

Question

An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3 Ω, then the phase difference between the applied voltage and the current in the circuit will be:

Accepted Answer

In a series RL circuit, the phase difference $\phi$ between the applied voltage and the current is determined by the tangent of the ratio of the inductive reactance ($X_L$) to the resistance ($R$). The relationship is given by $	an \phi = \frac{X_L}{R}$ .

Given:
$R = 3 \, \Omega$
$X_L = 3 \, \Omega$

Substituting these values:
$	an \phi = \frac{3}{3} = 1$

Therefore:
$\phi = 	an^{-1}(1) = 45^\circ = \frac{\pi}{4}$ rad.

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