An electric dipole is placed at an angle of $30^\circ$ with an electric field of intensity $2 imes 10^5$ N C

Question

An electric dipole is placed at an angle of $30^\circ$ with an electric field of intensity $2 	imes 10^5$ N C$^{-1}$. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

Accepted Answer

Torque $	au = pE \sin	heta$, where $p = q 	imes (2a)$. Given $	au = 4$ N m, $E = 2 	imes 10^5$ N C$^{-1}$, $	heta = 30^\circ$, $2a = 2$ cm = $0.02$ m. $4 = q 	imes 0.02 	imes 2 	imes 10^5 	imes \sin(30^\circ)$. $4 = q 	imes 0.02 	imes 2 	imes 10^5 	imes 0.5$. $4 = q 	imes 2000$. $q = 4 / 2000 = 0.002$ C = 2 mC.

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