An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly)

Question

An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) : ($m_e = 9 	imes 10^{-31}$ kg)

Accepted Answer

For an electron accelerated through a potential V, $\lambda = \frac{12.27}{\sqrt{V}} 	ext{ \AA} = \frac{12.27 	imes 10^{-10}}{\sqrt{10000}} = 12.27 	imes 10^{-12}$ m

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