Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head

Question

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body A is :

Accepted Answer

The fractional loss of kinetic energy is given by $\frac{\Delta KE}{KE} = \frac{4(m_1 m_2)}{(m_1 + m_2)^2}$. Substituting $m_1 = 4m$ and $m_2 = 2m$, we get $\frac{4(4m)(2m)}{(4m + 2m)^2} = \frac{32m^2}{36m^2} = \frac{8}{9}$.

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