If the dimensions of a physical quantity are given by $[M^a L^b T^c]$, then the physical quantity will be:

Question

Accepted Answer

Let us check the dimensions of each given physical quantity:
1. **Pressure**: $	ext{Pressure} = \frac{	ext{Force}}{	ext{Area}} = \frac{[M L T^{-2}]}{[L^2]} = [M^1 L^{-1} T^{-2}]$. Comparing with $[M^a L^b T^c]$, we get $a=1, b=-1, c=-2$. This matches the first option.
2. **Velocity**: $	ext{Velocity} = [M^0 L^1 T^{-1}]$. Here $a=0, b=1, c=-1$.
3. **Acceleration**: $	ext{Acceleration} = [M^0 L^1 T^{-2}]$. Here $a=0, b=1, c=-2$.
4. **Force**: $	ext{Force} = [M^1 L^1 T^{-2}]$. Here $a=1, b=1, c=-2$.

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