In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima f

Question

In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? ($\mu_{water} = 4/3$)

Accepted Answer

In air, $	heta_0 = \frac{\beta}{D}$. In water, the angular width becomes $	heta_w = \frac{	heta_0}{\mu} = \frac{0.2°}{4/3} = 0.15°$.

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