In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally

Question

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 	imes 10^{10}$ Hz and amplitude $48$ V m$^{-1}$. Then the amplitude of oscillating magnetic field is (Speed of light in free space = $3 	imes 10^8$ m s$^{-1}$)

Accepted Answer

The relation between electric field amplitude $E_0$ and magnetic field amplitude $B_0$ is $B_0 = \frac{E_0}{c}$. Given $E_0 = 48$ V m$^{-1}$ and $c = 3 	imes 10^8$ m s$^{-1}$, $B_0 = \frac{48}{3 	imes 10^8} = 16 	imes 10^{-8} = 1.6 	imes 10^{-7}$ T.

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