In a potentiometer circuit a cell of EMF $1.5 \ V$ gives balance point at $36 \ cm$ length of wire. If another

Question

In a potentiometer circuit a cell of EMF $1.5 \ V$ gives balance point at $36 \ cm$ length of wire. If another cell of EMF $2.5 \ V$ replaces the first cell, then at what length of the wire, the balance point occurs?

Accepted Answer

From the application of potentiometer to compare two cells of emfs $E_1$ and $E_2$ by balancing lengths $\ell_1$ and $\ell_2$, we have $E_1/E_2 = \ell_1/\ell_2$. Thus, $\ell_2 = \ell_1(E_2/E_1) = (36 \ cm)(2.5 \ V / 1.5 \ V) = 60 \ cm$.

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