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NEET PHYSICSUNITS AND MEASUREMENTSMedium

Question

Inductance LL can be dimensionally represented as:

A

ML2T−2A−2ML^2T^{-2}A^{-2}

B

ML2T−4A−3ML^2T^{-4}A^{-3}

C

ML−2T−2A−2ML^{-2}T^{-2}A^{-2}

D

ML2T4A3ML^2T^4A^3

Step-by-Step Solution

According to the sources, inductance (LL) is a scalar quantity defined by the ratio of magnetic flux linkage to current (L=NΦB/IL = N\Phi_B / I) . The dimensions of magnetic flux (ΦB\Phi_B) are [ML2T−2A−1][ML^2T^{-2}A^{-1}] . Dividing this by the dimension of current ([A][A]) gives the dimensions of inductance as [ML2T−2A−2][ML^2T^{-2}A^{-2}] . Alternatively, this can be derived from the expression for magnetic energy stored in an inductor, W=12LI2W = \frac{1}{2}LI^2. Since energy (WW) has dimensions [ML2T−2][ML^2T^{-2}] and current (II) has dimension [A][A], the dimensions for LL are [ML2T−2]/[A]2=[ML2T−2A−2][ML^2T^{-2}]/[A]^2 = [ML^2T^{-2}A^{-2}] .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSinductancedimensionallyrepresented

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