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NEET PHYSICSATOMSMedium

Question

Magnetic moment due to the motion of the electron in the nth energy state of a hydrogen atom is proportional to

A

n

B

n⁰

C

n⁵

D

Step-by-Step Solution

According to the Bohr model, the orbital magnetic moment (μ\mu) of an electron is given by the product of the current (II) and the area of the orbit (AA).

  1. Current I=eT=ev2πrI = \frac{e}{T} = \frac{ev}{2\pi r}.
  2. Area A=πr2A = \pi r^2.
  3. Thus, μ=evr2\mu = \frac{evr}{2}. From Bohr's postulates, the angular momentum mvr=nh2πmvr = \frac{nh}{2\pi} . Substituting vr=nh2πmvr = \frac{nh}{2\pi m} into the magnetic moment equation: μ=e2(nh2πm)=n(eh4πm)=nμB\mu = \frac{e}{2} \left( \frac{nh}{2\pi m} \right) = n \left( \frac{eh}{4\pi m} \right) = n \mu_B. Therefore, μn\mu \propto n.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ATOMS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSATOMSmagneticmomentmotionelectronenergy

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