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NEET PHYSICSMOTION IN A STRAIGHT LINEMedium

Question

The acceleration due to gravity on the planet A is 99 times the acceleration due to gravity on planet B. A man jumps to a height of 2 m2 \text{ m} on the surface of A. What is the height of jump by the same person on the planet B?

A

18 m

B

6 m

C

2/3 m

D

2/9 m

Step-by-Step Solution

  1. Identify the Principle: The height HH reached by a person jumping vertically depends on the initial velocity uu (supplied by the person's energy) and the acceleration due to gravity gg. Using the kinematic equation v2=u22gHv^2 = u^2 - 2gH (where final velocity v=0v=0 at max height), we get: H=u22gH = \frac{u^2}{2g}
  2. Analyze the Relationship: Assuming the person exerts the same effort, the initial velocity uu remains constant on both planets. Therefore, the height reached is inversely proportional to gravity (H1gH \propto \frac{1}{g}). HAgA=HBgBH_A g_A = H_B g_B
  3. Substitute Values:
  • Given: gA=9gBg_A = 9 g_B and HA=2 mH_A = 2 \text{ m}.
  • Substitute into the equation: 2×(9gB)=HB×gB2 \times (9 g_B) = H_B \times g_B 18gB=HBgB18 g_B = H_B g_B HB=18 mH_B = 18 \text{ m} .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEaccelerationgravityplanetaccelerationgravity

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