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NEET PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEEasy

Question

The diagrams below show regions of equipotentials. A positive charge is moved from A to B in each diagram. Then:

A

the maximum work is required to move q in figure(iii).

B

in all four cases, the work done is the same.

C

the minimum work is required to move q in the figure(i).

D

the maximum work is required to move q in figure(ii).

Step-by-Step Solution

The work done (WW) in moving a charge qq from point A to point B in an electric field is given by the expression W=q(VB−VA)W = q(V_B - V_A), where VBV_B and VAV_A are the electric potentials at the final and initial positions, respectively [1]. This work done is independent of the path taken and the shape of the electric field lines or equipotential surfaces [2]. Since the potential difference (VB−VA)(V_B - V_A) is the same for all four diagrams (assuming standard potential values usually depicted in this problem, e.g., moving between the same potential values in different field configurations), the work done is identical in all cases.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROSTATIC POTENTIAL AND CAPACITANCE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEdiagramsregionsequipotentialspositivecharge

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