back to directory
NEET PHYSICSUNITS AND MEASUREMENTSEasy

Question

The dimensional formula of relative density is:

A

ML−3ML^{-3}

B

LT−1LT^{-1}

C

MLT−2MLT^{-2}

D

Dimensionless

Step-by-Step Solution

  1. Define Relative Density: Relative density is defined as the ratio of the density of a substance to the density of a reference substance (usually water at 4∘C4^\circ\text{C}).
  2. Identify Dimensions: Since it is the ratio of two identical physical quantities (density), their dimensions cancel each other out . Relative Density=Density of substanceDensity of water=[ML−3][ML−3]=[M0L0T0]\text{Relative Density} = \frac{\text{Density of substance}}{\text{Density of water}} = \frac{[ML^{-3}]}{[ML^{-3}]} = [M^0L^0T^0]
  3. Conclusion: Because the dimensional formula is [M0L0T0][M^0L^0T^0], relative density is a dimensionless quantity.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSdimensionalformularelativedensity

More UNITS AND MEASUREMENTS Questions

View all

In an experiment, four quantities $a$, $b$, $c$ and $d$ are measured with percentage error $1\%$, $2\%$, $3\%$ and $4\%$ respectively. Quantity $P$ is calculated as follows: $P=\frac{a^3b^2}{cd}$. Percentage error in $P$ is:

A.$10\%$
B.$7\%$
C.$4\%$
D.$14\%$
MediumSolve

Dimensional formula for volume elasticity is

A.M¹L⁻²T⁻²
B.M¹L⁻³T⁻²
C.M¹L²T⁻²
D.M¹L⁻¹T⁻²
EasySolve

The velocity $v$ of a particle at time $t$ is given by $v = at + \frac{b}{t+c}$, where $a$, $b$ and $c$ are constants. The dimensions of $a$, $b$ and $c$ are respectively:

A.$[L T^{-2}], [L]$ and $[T]$
B.$[L^2], [T]$ and $[LT^2]$
C.$[LT^2], [LT]$ and $[L]$
D.$[L], [LT]$ and $[T^2]$
MediumSolve

Which one has the dimensions different from the remaining three?

A.Power
B.Work
C.Torque
D.Energy
EasySolve

Taking into account the significant figures, what is the value of $9.99\text{ m} - 0.0099\text{ m}$?

A.$9.98\text{ m}$
B.$9.980\text{ m}$
C.$9.9\text{ m}$
D.$9.9801\text{ m}$
EasySolve

Of the following quantities, which one has dimensions different from the remaining three?

A.Energy per unit volume
B.Force per unit area
C.Product of voltage and charge per unit volume
D.Angular momentum per unit mass
MediumSolve

If the unit of length and force be increased four times, then the unit of energy is:

A.Increased 4 times
B.Increased 8 times
C.Increased 16 times
D.Decreased 16 times
EasySolve

Which of the following pairs of physical quantities has the same dimensions?

A.Work and power
B.Momentum and energy
C.Force and power
D.Work and energy
EasySolve

Why 32,000+ students choose TopperSquare

Everything you need to crack NEET

15,000+ Chapter MCQs

Physics, Chemistry, Biology — chapter-wise, topic-wise practice

AI Performance Analytics

Know your weak topics. Get a personalised study plan.

Full NEET Mock Tests

180 questions, timed, with detailed score analysis

PYQ Sets 2010–2024

15 years of past papers with solved explanations

Start Practising Free

No credit card · 30-second signup · Free forever plan included

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →

Explore more subjects:Physics MCQs•Chemistry MCQs•Biology MCQs•Botany MCQs•Zoology MCQs•NEET Mock Tests•NEET PYQs