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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

The distance travelled by a particle is proportional to the squares of time, then the particle travels with:

A

Uniform acceleration

B

Uniform velocity

C

Increasing acceleration

D

Decreasing velocity

Step-by-Step Solution

  1. Mathematical Relationship: Given that the distance (ss) is proportional to the square of time (t2t^2), we can express this as s=kt2s = kt^2, where kk is a constant.
  2. Velocity: The instantaneous velocity (vv) is the first derivative of distance with respect to time (v=dsdtv = \frac{ds}{dt}). Differentiating s=kt2s = kt^2, we get v=2ktv = 2kt.
  3. Acceleration: The acceleration (aa) is the rate of change of velocity (a=dvdta = \frac{dv}{dt}). Differentiating v=2ktv = 2kt, we get a=2ka = 2k.
  4. Conclusion: Since kk is a constant, 2k2k is also a constant. This implies the acceleration is uniform (constant) throughout the motion. This aligns with the kinematic equation for a body starting from rest (u=0u=0): s=12at2s = \frac{1}{2}at^2, where st2s \propto t^2 .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEdistancetravelledparticleproportionalsquares

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