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NEET PHYSICSUNITS AND MEASUREMENTSEasy

Question

The equation of a wave is given by Y=Asinω(xvk)Y = A \sin \omega (\frac{x}{v} - k) where ω\omega is the angular velocity, xx is length and vv is the linear velocity. The dimension of kk is:

A

LT

B

T

C

T⁻¹

D

Step-by-Step Solution

To find the dimensions of kk, we utilize the Principle of Homogeneity of dimensions, which states that only physical quantities of the same dimensions can be added or subtracted .

  1. Analyze the term (xvk)(\frac{x}{v} - k): Since kk is subtracted from the term xv\frac{x}{v}, both terms must have the same dimensional formula.
  2. Determine dimensions of xv\frac{x}{v}: xx (Length) has dimensions [L][L]. vv (Linear Velocity) has dimensions [LT1][LT^{-1}] .
  • Therefore, the dimensions of xv\frac{x}{v} are [L][LT1]=[T]\frac{[L]}{[LT^{-1}]} = [T].
  1. Conclusion: Since dimensions of kk must equal dimensions of xv\frac{x}{v}, the dimension of kk is [T][T].

Note: The argument of the sine function, ω(xvk)\omega(\frac{x}{v} - k), must be dimensionless. Checking: [ω]×[T]=[T1]×[T]=[\omega] \times [T] = [T^{-1}] \times [T] = , which confirms the validity of the equation.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSequationfracxvangularvelocitylength

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