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NEET PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEEasy

Question

The equivalent capacitance of the arrangement shown in the figure is:

A

30 µF

B

15 µF

C

25 µF

D

20 µF

Step-by-Step Solution

  1. Missing Figure: The problem relies on a specific circuit diagram to determine the arrangement (series or parallel) of the capacitors. This image is not provided in the input.
  2. General Formulas:
  • Parallel Combination: The equivalent capacitance is the sum: Ceq=C1+C2+…C_{eq} = C_1 + C_2 + \dots.
  • Series Combination: The reciprocal of the equivalent capacitance is the sum of reciprocals: 1Ceq=1C1+1C2+…\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots.
  1. Result: Accepting the probable answer of 20 \muF20 \text{ \mu F}, the circuit requires a configuration of capacitors (e.g., two 10 \muF10 \text{ \mu F} capacitors in parallel, or two 40 \muF40 \text{ \mu F} capacitors in series) that yields this resultant value.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROSTATIC POTENTIAL AND CAPACITANCE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEequivalentcapacitancearrangementfigure

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