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NEET PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEEasy

Question

The equivalent capacitance of the system shown in the following circuit is:

A

9 \mu F

B

2 \mu F

C

3 \mu F

D

6 \mu F

Step-by-Step Solution

  1. Missing Diagram: The problem requires a circuit diagram to determine the specific arrangement (series/parallel) of the capacitors.
  2. General Principles:
  • Parallel Combination: Capacitors connected in parallel have an equivalent capacitance Cp=C1+C2+…C_p = C_1 + C_2 + \dots.
  • Series Combination: Capacitors connected in series have an equivalent capacitance given by 1Cs=1C1+1C2+…\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} + \dots.
  1. Hypothetical Scenario: For an answer of 2 \muF2 \text{ \mu F}, a common configuration in such exams involving 3 \muF3 \text{ \mu F} capacitors is two capacitors in parallel (3+3=6 \muF3+3=6 \text{ \mu F}) connected in series with a third 3 \muF3 \text{ \mu F} capacitor. The equivalent would be 6×36+3=189=2 \muF\frac{6 \times 3}{6 + 3} = \frac{18}{9} = 2 \text{ \mu F}. Without the image, this is a likely theoretical derivation.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROSTATIC POTENTIAL AND CAPACITANCE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEequivalentcapacitancesystemfollowingcircuit

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A.Option 1
B.Option 2
C.Option 3
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A.zero
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If potential in a region is expressed as $V(x,y,z) = 6xy - y + 2yz$, the electric field at point $(1, 1, 0)$ is:

A.$-(3\hat{i} + 5\hat{j} + 3\hat{k})$
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