The magnetic energy stored in an inductor of inductance $4 ext{ }\mu ext{H}$ carrying a current of $2 ext

Question

The magnetic energy stored in an inductor of inductance $4 	ext{ }\mu	ext{H}$ carrying a current of $2 	ext{ A}$ is:

Accepted Answer

The magnetic potential energy ($U$) stored in an inductor is given by the formula:
$$U = \frac{1}{2} L I^2$$

**Given:**
*   Inductance ($L$) = $4 	ext{ }\mu	ext{H} = 4 	imes 10^{-6} 	ext{ H}$
*   Current ($I$) = $2 	ext{ A}$

**Calculation:**
$$U = \frac{1}{2} 	imes (4 	imes 10^{-6}) 	imes (2)^2$$
$$U = \frac{1}{2} 	imes 4 	imes 10^{-6} 	imes 4$$
$$U = 8 	imes 10^{-6} 	ext{ J}$$
$$U = 8 	ext{ }\mu	ext{J}$$

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