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NEET PHYSICSUNITS AND MEASUREMENTSEasy

Question

The surface tension of a liquid is 70 dyne/cm70\text{ dyne/cm}. In MKS system its value is

A

70 N/m70\text{ N/m}

B

7×10−2 N/m7 \times 10^{-2}\text{ N/m}

C

7×103 N/m7 \times 10^3\text{ N/m}

D

7×102 N/m7 \times 10^2\text{ N/m}

Step-by-Step Solution

To convert surface tension from CGS units (dyne/cm) to MKS/SI units (N/m), we apply the standard unit conversion factors : 1 N=105 dyne  ⟹  1 dyne=10−5 N1\text{ N} = 10^5\text{ dyne} \implies 1\text{ dyne} = 10^{-5}\text{ N} 1 m=102 cm  ⟹  1 cm=10−2 m1\text{ m} = 10^2\text{ cm} \implies 1\text{ cm} = 10^{-2}\text{ m} Therefore, 70 dyne/cm=70×10−5 N10−2 m=70×10−3 N/m=7×10−2 N/m70\text{ dyne/cm} = 70 \times \frac{10^{-5}\text{ N}}{10^{-2}\text{ m}} = 70 \times 10^{-3}\text{ N/m} = 7 \times 10^{-2}\text{ N/m}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSsurfacetensionliquiddynecmsystem

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