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NEET PHYSICSUNITS AND MEASUREMENTSEasy

Question

The unit of permittivity of free space ε0\varepsilon_0 is

A

Coulomb/Newton-metre\text{Coulomb} / \text{Newton-metre}

B

Newton-metre2/Coulomb2\text{Newton-metre}^2 / \text{Coulomb}^2

C

Coulomb2/(Newton-metre)2\text{Coulomb}^2 / (\text{Newton-metre})^2

D

Coulomb2/Newton-metre2\text{Coulomb}^2 / \text{Newton-metre}^2

Step-by-Step Solution

According to Coulomb's law, the electrostatic force between two point charges is given by F=14πε0q1q2r2F = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r^2}. Rearranging this formula for the permittivity of free space (ε0\varepsilon_0), we get ε0=14πFq1q2r2\varepsilon_0 = \frac{1}{4\pi F} \frac{q_1 q_2}{r^2}. Substituting the SI units for charge (C), force (N), and distance (m), the unit of ε0\varepsilon_0 is C⋅CN⋅m2=C2 N−1 m−2\frac{\text{C} \cdot \text{C}}{\text{N} \cdot \text{m}^2} = \text{C}^2 \text{ N}^{-1} \text{ m}^{-2} or Coulomb2/Newton-metre2\text{Coulomb}^2 / \text{Newton-metre}^2.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSpermittivityvarepsilon

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