Two hollow conducting spheres of radii $R_1$ and $R_2$ ($R_1 R_2$) have equal charges. The potential would

Question

Two hollow conducting spheres of radii $R_1$ and $R_2$ ($R_1 >> R_2$) have equal charges. The potential would be

Accepted Answer

Potential of a conducting hollow sphere is given by $V = \frac{KQ}{R}$. Since the charge $Q$ is the same for both, $V \propto \frac{1}{R}$. Therefore, the smaller the radius, the higher the potential. Thus, the potential is higher on the smaller sphere.

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