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NEET PHYSICSMOVING CHARGES AND MAGNETISMEasy

Question

Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry the same current i, what will be the ratio of the magnetic fields along the two loops?

A

1:1

B

4:1

C

2:1

D

1:2

Step-by-Step Solution

  1. Formula: The magnetic field BB inside a toroid is given by the formula: B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r} where NN is the total number of turns, II is the current, and rr is the average radius of the toroid .
  2. Given Values:
  • Toroid 1: N1=200N_1 = 200, r1=40 cm=0.4 mr_1 = 40 \text{ cm} = 0.4 \text{ m}, Current = ii.
  • Toroid 2: N2=100N_2 = 100, r2=20 cm=0.2 mr_2 = 20 \text{ cm} = 0.2 \text{ m}, Current = ii.
  1. Calculation of Ratio (B1/B2B_1/B_2): B1B2=μ0N1i2πr1μ0N2i2πr2\frac{B_1}{B_2} = \frac{\frac{\mu_0 N_1 i}{2\pi r_1}}{\frac{\mu_0 N_2 i}{2\pi r_2}} B1B2=(N1r1)×(r2N2)\frac{B_1}{B_2} = \left( \frac{N_1}{r_1} \right) \times \left( \frac{r_2}{N_2} \right) B1B2=(20040)×(20100)\frac{B_1}{B_2} = \left( \frac{200}{40} \right) \times \left( \frac{20}{100} \right) B1B2=5×0.2=1\frac{B_1}{B_2} = 5 \times 0.2 = 1 Thus, the ratio is 1:1.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOVING CHARGES AND MAGNETISM. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOVING CHARGES AND MAGNETISMtoroidsrespectivelyaveragerespectivelycurrent

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