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NEET CHEMISTRYSome Basic Concepts of ChemistryEasy

Question

1 M, 2.5 litre NaOH solution is mixed with another 0.5 M and 3 litre NaOH solution. The molarity of the resultant solution will be:

A

0.80 M

B

1.0 M

C

0.73 M

D

0.50 M

Step-by-Step Solution

  1. Identify the Principle: Molarity (MM) is defined as the number of moles of solute dissolved in one litre of solution . When mixing two solutions of the same solute, the total number of moles is the sum of the moles in each solution, and the total volume is the sum of the individual volumes.
  2. Calculate Moles in Solution 1 (n1n_1): n1=M1×V1=1 M×2.5 L=2.5 moln_1 = M_1 \times V_1 = 1\text{ M} \times 2.5\text{ L} = 2.5\text{ mol}
  3. Calculate Moles in Solution 2 (n2n_2): n2=M2×V2=0.5 M×3 L=1.5 moln_2 = M_2 \times V_2 = 0.5\text{ M} \times 3\text{ L} = 1.5\text{ mol}
  4. Calculate Resultant Molarity (MmixM_{mix}): ntotal=n1+n2=2.5+1.5=4.0 moln_{total} = n_1 + n_2 = 2.5 + 1.5 = 4.0\text{ mol} Vtotal=V1+V2=2.5+3.0=5.5 LV_{total} = V_1 + V_2 = 2.5 + 3.0 = 5.5\text{ L} Mmix=ntotalVtotal=4.05.50.727 MM_{mix} = \frac{n_{total}}{V_{total}} = \frac{4.0}{5.5} \approx 0.727\text{ M}
  5. Rounding: The value rounds to approximately 0.73 M0.73\text{ M}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Some Basic Concepts of Chemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYSome Basic Concepts of Chemistrysolutionanothersolutionmolarityresultant

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