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NEET CHEMISTRYCoordination CompoundsMedium

Question

A complex compound is formed by ligands nitrate and chloride. It gives two moles of AgCl precipitate with AgNO3AgNO_3. What will its formula be?

A

[Co(NH3)5NO3]Cl2[Co(NH_3)_5NO_3]Cl_2

B

[Co(NH3)5Cl]NO3Cl[Co(NH_3)_5Cl]NO_3Cl

C

[Co(NH3)4Cl2]NO3[Co(NH_3)_4Cl_2]NO_3

D

[Co(NH3)4ClNO3]Cl[Co(NH_3)_4ClNO_3]Cl

Step-by-Step Solution

According to Werner's theory of coordination compounds, the ions present outside the coordination sphere (in the ionization sphere) are ionisable. When the complex reacts with silver nitrate (AgNO3AgNO_3), it gives a precipitate of AgCl corresponding to the number of chloride ions present outside the coordination sphere. Since the complex gives two moles of AgCl precipitate per mole of the compound, it must have two ionisable chloride ions outside the square bracket. Among the given options, only [Co(NH3)5NO3]Cl2[Co(NH_3)_5NO_3]Cl_2 satisfies this condition, as it yields two Cl−Cl^- ions in aqueous solution.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscomplexcompoundformedligandsnitrate

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
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D.$[Co(NH_3)_6]^{3+}$
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Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
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