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NEET CHEMISTRYCoordination CompoundsMedium

Question

The complex, [Pt(Py)(NH3)BrCl][\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}] will have how many geometrical isomers?

A

4

B

0

C

2

D

3

Step-by-Step Solution

The given complex [Pt(Py)(NH3)BrCl][\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}] is a square planar complex of the type [Mabcd][Mabcd] (or MABXLMABXL), where all four ligands are different unidentate ligands. According to coordination chemistry principles, such a complex exhibits three geometrical isomers (two cis and one trans). These can be determined by fixing one ligand at a specific position and placing the other three ligands trans to it one by one .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscomplextextpttextpytextnhtextbrclgeometricalisomers

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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
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Mg is present in:

A.Chlorophyll
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C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
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Number of isomers of $[Pt(NH_3)_4][CuCl_4]$ complex are:

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