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NEET CHEMISTRYCoordination CompoundsEasy

Question

The complexes [Co(NH3)6][Cr(CN)6][\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6] and [Cr(NH3)6][Co(CN)6][\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6] are examples of:

A

Ionisation isomerism

B

Coordination isomerism

C

Geometrical isomerism

D

Linkage isomerism

Step-by-Step Solution

This type of isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex. An example is provided by [Co(NH3)6][Cr(CN)6][\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6], in which the NH3\text{NH}_3 ligands are bound to Co3+\text{Co}^{3+} and the CN−\text{CN}^- ligands to Cr3+\text{Cr}^{3+}. In its coordination isomer [Cr(NH3)6][Co(CN)6][\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6], the NH3\text{NH}_3 ligands are bound to Cr3+\text{Cr}^{3+} and the CN−\text{CN}^- ligands to Co3+\text{Co}^{3+}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscomplexestextcotextnhtextcrtextcntextcrtextnhtextcotextcnexamples

More Coordination Compounds Questions

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
MediumSolve

Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
MediumSolve

Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
EasySolve

The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
D.$[Cr(SCN)_2(NH_3)_4]^+$
HardSolve

$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
B.$Cu(NO_3)_2$
C.$[Cu(H_2O)_4]^{2+}$
D.None of the above
MediumSolve

CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
D.[Co(C₂O₄)₃]³⁻
MediumSolve

The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
B.Dicyanidosilver(II) diaquaargentate(II)
C.Diaquasilver(II) dicyanidoargentate(II)
D.Dicyanidosilver(I) diaquaargentate(I)
EasySolve

Number of isomers of $[Pt(NH_3)_4][CuCl_4]$ complex are:

A.2
B.3
C.4
D.5
MediumSolve

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