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NEET CHEMISTRYCoordination CompoundsMedium

Question

[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+} reacts with HNO3HNO_3 in excess of water and gives:

A

Cu(OH)2Cu(OH)_2

B

Cu(NO3)2Cu(NO_3)_2

C

[Cu(H2O)4]2+[Cu(H_2O)_4]^{2+}

D

None of the above

Step-by-Step Solution

When a strong acid like nitric acid (HNO3HNO_3) is added to the tetraamminecopper(II) complex [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}, the acid protonates the basic ammonia (NH3NH_3) ligands to form ammonium ions (NH4+NH_4^+). This breaks the complex, releasing Cu2+Cu^{2+} ions into the aqueous solution. The Cu2+Cu^{2+} ions combine with the available nitrate (NO3NO_3^-) ions from the acid to form copper(II) nitrate. The reaction can be summarised as: [Cu(NH3)4]2++4HNO3ightarrowCu(NO3)2+4NH4++2NO3[Cu(NH_3)_4]^{2+} + 4HNO_3 ightarrow Cu(NO_3)_2 + 4NH_4^+ + 2NO_3^-. Therefore, aqueous Cu(NO3)2Cu(NO_3)_2 is obtained.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundsreactsexcess

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