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NEET CHEMISTRYCoordination CompoundsEasy

Question

The IUPAC name of the following complex is: [Ag(H2O)2][Ag(CN)2][Ag(H_2O)_2][Ag(CN)_2]

A

Diaquasilver(I) dicyanidoargentate(I)

B

Dicyanidosilver(II) diaquaargentate(II)

C

Diaquasilver(II) dicyanidoargentate(II)

D

Dicyanidosilver(I) diaquaargentate(I)

Step-by-Step Solution

The given coordination compound [Ag(H2O)2][Ag(CN)2][Ag(H_2O)_2][Ag(CN)_2] is composed of a complex cation [Ag(H2O)2]+[Ag(H_2O)_2]^+ and a complex anion [Ag(CN)2]−[Ag(CN)_2]^-. Let the oxidation state of silver in both coordination spheres be xx. Since the overall charge of the compound is zero, we can calculate the oxidation state as: x+2(0)+x+2(−1)=0⇒2x−2=0⇒x=+1x + 2(0) + x + 2(-1) = 0 \Rightarrow 2x - 2 = 0 \Rightarrow x = +1. Thus, the oxidation state of Ag is +1 in both the cationic and anionic entities.

  • For the cationic part [Ag(H2O)2]+[Ag(H_2O)_2]^+, the ligands are neutral water molecules named 'aqua', and the metal is named 'silver'. So, it is named diaquasilver(I).
  • For the anionic part [Ag(CN)2]−[Ag(CN)_2]^-, the ligands are anionic cyanide ions named 'cyanido', and the metal name ends with '-ate', using its Latin root 'argentum'. So, it is named dicyanidoargentate(I). Combining the two parts (cation first, then anion), the full IUPAC name is diaquasilver(I) dicyanidoargentate(I).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundsfollowingcomplexaghoagcn

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

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Mg is present in:

A.Chlorophyll
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

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