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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

Amongst the following, which one will have maximum 'lone pair - lone pair' electron repulsions?

A

XeF2XeF_2

B

ClF3ClF_3

C

IF5IF_5

D

SF4SF_4

Step-by-Step Solution

According to the Valence Shell Electron Pair Repulsion (VSEPR) theory, the magnitude of repulsive interactions between electron pairs follows the order: Lone pair (lp) – Lone pair (lp) > Lone pair (lp) – Bond pair (bp) > Bond pair (bp) – Bond pair (bp) .

To determine which molecule has the maximum lone pair - lone pair repulsion, we count the lone pairs on the central atom of each molecule:

  1. XeF2XeF_2: Xenon (group 18) has 8 valence electrons. Two are used for bonding, leaving 6 electrons which form 3 lone pairs .
  2. ClF3ClF_3: Chlorine (group 17) has 7 valence electrons. Three are used for bonding, leaving 4 electrons which form 2 lone pairs .
  3. IF5IF_5: Iodine (group 17) has 7 valence electrons. Five are used for bonding, leaving 2 electrons which form 1 lone pair .
  4. SF4SF_4: Sulphur (group 16) has 6 valence electrons. Four are used for bonding, leaving 2 electrons which form 1 lone pair .

Since XeF2XeF_2 has the highest number of lone pairs (3), it will experience the maximum 'lone pair - lone pair' electron repulsions among the given options.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques amongstfollowingmaximumelectronrepulsions

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