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NEET CHEMISTRYChemical Bonding and Molecular StructureMedium

Question

dπpπd\pi - p\pi bond is present in:

A

CO32CO_{3}^{2-}

B

PO43PO_{4}^{3-}

C

NO3NO_{3}^{-}

D

NO2NO_{2}^{-}

Step-by-Step Solution

The formation of dπpπd\pi - p\pi bonds is determined by the availability of dd-orbitals in the valence shell of the central atom. According to the sources, second-period elements such as Carbon (CC) and Nitrogen (NN) have only four valence orbitals (2s2s and 2p2p) and lack dd-orbitals . As a result, these elements primarily form pπpπp\pi - p\pi multiple bonds with themselves or other second-period elements like Oxygen . This is the case for CO32CO_{3}^{2-}, NO3NO_{3}^{-}, and NO2NO_{2}^{-}. However, third-period elements like Phosphorus (PP) have vacant 3d3d orbitals available for bonding in addition to their ss and pp orbitals . In the phosphate ion (PO43PO_{4}^{3-}), the central phosphorus atom can expand its octet and use its dd-orbitals to overlap with the pp-orbitals of oxygen, resulting in the presence of dπpπd\pi - p\pi bonds.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structurepresent

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