Find the molarity of liquid HCl if the density of liquid HCl is $1.17 ext{ g/cc}$.

Question

Find the molarity of liquid HCl if the density of liquid HCl is $1.17	ext{ g/cc}$.

Accepted Answer

1. **Identify the Definition:** Molarity ($M$) is defined as the number of moles of solute dissolved in one litre of solution .
2. **Assumption:** Consider exactly $1	ext{ Litre}$ ($1000	ext{ cc}$ or $1000	ext{ mL}$) of the liquid HCl.
3. **Calculate Mass:** Using the given density ($d = 1.17	ext{ g/cc}$):
   $$ 	ext{Mass} = 	ext{Density} 	imes 	ext{Volume} = 1.17	ext{ g/cc} 	imes 1000	ext{ cc} = 1170	ext{ g} $$
4. **Calculate Moles:** The molar mass of HCl ($1 + 35.5$) is $36.5	ext{ g/mol}$.
   $$ 	ext{Moles} (n) = \frac{	ext{Mass}}{	ext{Molar Mass}} = \frac{1170}{36.5} \approx 32.05	ext{ mol} $$
5. **Calculate Molarity:**
   $$ M = \frac{n}{V(	ext{in L})} = \frac{32.05	ext{ mol}}{1	ext{ L}} = 32.05	ext{ M} $$

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