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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

Identify the incorrect statement among the following:

A

The H-O-H bond angle in H₂O is larger than the H-C-H bond angle in CH₄

B

The H-C-H bond angle in CH₄ is larger than the H-N-H bond angle in NH₃

C

The H-C-H bond angle in CH₄, the H-N-H bond angle in NH₃ and the H-O-H bond angle in H₂O are all greater than 90°

D

The H-O-H bond angle in H₂O is smaller than the H-N-H bond angle in NH₃

Step-by-Step Solution

  1. Methane (CH₄): The central carbon atom is sp3sp^3 hybridised with 0 lone pairs. The molecule has a regular tetrahedral geometry with a bond angle of 109.5° .
  2. Ammonia (NH₃): The central nitrogen atom is sp3sp^3 hybridised but possesses 1 lone pair. According to VSEPR theory, the repulsion between the lone pair and bond pairs (lp−bplp-bp) is greater than between bond pairs (bp−bpbp-bp), causing the bond angle to decrease from 109.5° to 107° .
  3. Water (H₂O): The central oxygen atom is sp3sp^3 hybridised with 2 lone pairs. The repulsive interaction follows the order lp−lp>lp−bp>bp−bplp-lp > lp-bp > bp-bp. The presence of two lone pairs squeezes the bond angle further to 104.5° .
  4. Verification of Statements:
  • Option A: States H₂O angle (104.5°) > CH₄ angle (109.5°). This is Incorrect.
  • Option B: States CH₄ angle (109.5°) > NH₃ angle (107°). This is Correct.
  • Option C: All angles (109.5°, 107°, 104.5°) are > 90°. This is Correct.
  • Option D: States H₂O angle (104.5°) < NH₃ angle (107°). This is Correct.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques identifyincorrectstatementfollowing

More Organic Chemistry – Some Basic Principles and Techniques Questions

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Which one of the following pairs is isostructural (i.e., having the same shape and hybridization)?

A.$\text{BCl}_3$ and $\text{BrCl}_3$
B.$\text{NH}_3$ and $\text{NO}_3^-$
C.$\text{NF}_3$ and $\text{BF}_3$
D.$\text{BF}_4^-$ and $\text{NH}_4^+$
MediumSolve

Among the following, isoelectronic species are:

A.$CO_{2}, NO_{2}$
B.$NO_{2}^{-}, CO_{2}$
C.$CN^{-}, CO$
D.$SO_{2}, CO_{2}$
EasySolve

Which one of the following pairs of species have the same bond order?

A.$\text{CO}$, $\text{NO}$
B.$\text{O}_2^-$, $\text{CN}^-$
C.$\text{CN}^-$, $\text{NO}^+$
D.$\text{N}^+$, $\text{CN}^+$
MediumSolve

In a regular octahedral molecule, $MX_{6}$, the number of $X–M–X$ bonds at 180º is:

A.Two
B.Six
C.Four
D.Three
EasySolve

Which of the following pairs of ions are isoelectronic and isostructural?

A.CO₃²⁻, SO₃²⁻
B.ClO₃⁻, CO₃²⁻
C.SO₃²⁻, NO₃⁻
D.ClO₃⁻, SO₃²⁻
MediumSolve

Which orbital does the additional electron occupy when $O_{2}$ is converted to the $O_{2}^{-}$ ion?

A.$\pi$ orbital
B.$\sigma^{*}$ orbital
C.$\sigma$ orbital
D.$\pi^{*}$ orbital
MediumSolve

A species that does not exhibit paramagnetism is:

A.$N_{2}^{+}$
B.$O_{2}^{-}$
C.$CO$
D.$NO$
MediumSolve

The total number of $\pi$-bond electrons in the following structure is:

A.4
B.8
C.12
D.16
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