In the hydrocarbon $\overset{6}{C}H_3-\overset{5}{C}H=\overset{4}{C}H-\overset{3}{C}H_2-\overset{2}{C}\equiv\o

Question

In the hydrocarbon $\overset{6}{C}H_3-\overset{5}{C}H=\overset{4}{C}H-\overset{3}{C}H_2-\overset{2}{C}\equiv\overset{1}{C}H$, the state of hybridisation of carbons 1, 3 and 5 are in the following sequence:

Accepted Answer

In the given hydrocarbon:
Carbon-1 is involved in a triple bond, so it is $sp$ hybridized.
Carbon-3 is bonded via four single bonds, so it is $sp^3$ hybridized.
Carbon-5 is involved in a double bond, so it is $sp^2$ hybridized.
Therefore, the sequence of hybridization states for carbons 1, 3, and 5 is $sp$, $sp^3$, and $sp^2$ respectively.

Step-by-Step Solution

Practice All CHEMISTRY Questions