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NEET CHEMISTRYChemical Bonding and Molecular StructureEasy

Question

In the hydrocarbon C6H3−C5H=C4H−C3H2−C2≡C1H\overset{6}{C}H_3-\overset{5}{C}H=\overset{4}{C}H-\overset{3}{C}H_2-\overset{2}{C}\equiv\overset{1}{C}H, the state of hybridisation of carbons 1, 3 and 5 are in the following sequence:

A

sp2sp^2, spsp, sp3sp^3

B

spsp, sp3sp^3, sp2sp^2

C

spsp, sp2sp^2, sp3sp^3

D

sp3sp^3, sp2sp^2, spsp

Step-by-Step Solution

In the given hydrocarbon: Carbon-1 is involved in a triple bond, so it is spsp hybridized. Carbon-3 is bonded via four single bonds, so it is sp3sp^3 hybridized. Carbon-5 is involved in a double bond, so it is sp2sp^2 hybridized. Therefore, the sequence of hybridization states for carbons 1, 3, and 5 is spsp, sp3sp^3, and sp2sp^2 respectively.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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