Match List-I (Molecules) with List-II (Shapes):

List-I:
(a) $PCl_5$
(b) $SF_6$
(c) $BrF_5$
(d) $BF_3$

List-I

Question

Match List-I (Molecules) with List-II (Shapes):

List-I:
(a) $PCl_5$
(b) $SF_6$
(c) $BrF_5$
(d) $BF_3$

List-II:
(i) Square pyramidal
(ii) Trigonal planar
(iii) Octahedral
(iv) Trigonal bipyramidal

Choose the correct answer from the options given below:

Accepted Answer

According to the Valence Shell Electron Pair Repulsion (VSEPR) theory and the principles of hybridisation described in the sources:

1.  **$PCl_5$ (a)**: The central phosphorus atom undergoes $sp^3d$ hybridisation. With five bonding pairs and no lone pairs, it adopts a **trigonal bipyramidal** geometry .
2.  **$SF_6$ (b)**: The central sulphur atom undergoes $sp^3d^2$ hybridisation. With six bonding pairs, it forms a regular **octahedral** geometry .
3.  **$BrF_5$ (c)**: Bromine has seven valence electrons. It forms five sigma bonds with fluorine and has one lone pair ($sp^3d^2$ hybridisation). This 5 bond pair + 1 lone pair arrangement results in a **square pyramidal** shape .
4.  **$BF_3$ (d)**: Boron undergoes $sp^2$ hybridisation, forming three bond pairs with no lone pairs. This results in a **trigonal planar** geometry .

Matching these correctly results in (a)-(iv), (b)-(iii), (c)-(i), and (d)-(ii), which corresponds to option 3.

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