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NEET CHEMISTRYAminesMedium

Question

Match List-I with List-II:

List-I (Test) (a) Carbylamine test (b) Baeyer's test (c) Iodoform test (d) Phthalein dye test

List-II (Compound) (i) Phenol (ii) Acetone (iii) Ethylene (iv) Aniline

Choose the correct answer from the options given below:

A

(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

B

(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

C

(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

D

(a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)

Step-by-Step Solution

Let's match the chemical tests with their respective target compounds:

  1. Carbylamine test: This is a characteristic test for primary amines (both aliphatic and aromatic). Aniline is a primary aromatic amine and gives a positive carbylamine test by forming a foul-smelling isocyanide. [(a) \rightarrow (iv)]
  2. Baeyer's test: This test is used to detect the presence of unsaturation (carbon-carbon double or triple bonds). Ethylene contains a double bond and will decolourise the cold, dilute alkaline KMnO4KMnO_4 solution (Baeyer's reagent). [(b) \rightarrow (iii)]
  3. Iodoform test: This test is given by compounds having a methyl ketone group (COCH3-COCH_3) or a methyl carbinol group. Acetone (CH3COCH3CH_3COCH_3) contains a methyl ketone group and forms a yellow precipitate of iodoform (CHI3CHI_3) upon reaction with iodine and alkali. [(c) \rightarrow (ii)]
  4. Phthalein dye test: This test is specific for phenols. Phenol reacts with phthalic anhydride in the presence of concentrated H2SO4H_2SO_4 to form phenolphthalein, which turns pink in an alkaline medium. [(d) \rightarrow (i)]

Therefore, the correct matching is (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Amines. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAmineslistiicarbylaminebaeyersiodoformphthalein

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The products formed when Aniline reacts with $Br_2$ water, and $NaNO_2/HCl$ will be, respectively:

A.p-Bromoaniline; p-Chloroaniline
B.2,4,6-Tribromoaniline; p-Chloroaniline
C.2,4,6-Tribromoaniline; Benzenediazonium chloride
D.p-Bromoaniline; Benzenediazonium chloride
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Aniline gives a set of the following reactions that yielded a coloured product 'Y'. The structure of 'Y' is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
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The structure of C in the below-mentioned reaction is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
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What results from the electrolytic reduction of nitrobenzene in a highly acidic medium?

A.p-Aminophenol
B.Azoxybenzene
C.Azobenzene
D.Aniline
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The reagent required to convert acetamide into methyl amine is:

A.$NaOH/Br_2$
B.Sodalime
C.Hot conc. $H_2SO_4$
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A.Option 1 (Missing)
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Which of the following statements about primary amines is false?

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B.Alkyl amines react with nitrous acid to produce alcohols
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D.Alkyl amines are stronger bases than ammonia
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A.$CH_3NH_2 > (CH_3)_2NH > (CH_3)_3N$
B.$(CH_3)_2NH > CH_3NH_2 > (CH_3)_3N$
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