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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

The total number of π\pi-bond electrons in the following structure is:

A

4

B

8

C

12

D

16

Step-by-Step Solution

Although the specific structure is missing from the provided text, the number of π\pi-bond electrons can be calculated by multiplying the number of π\pi bonds by 2 (since each π\pi bond consists of a shared pair of 2 electrons). In the original NEET 2015 question, the given structure contained exactly 4 double bonds (which implies 4 σ\sigma bonds and 4 π\pi bonds). Therefore, the total number of π\pi-bond electrons is 4×2=84 \times 2 = 8.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques numberpibondelectronsfollowingstructure

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Which one of the following pairs is isostructural (i.e., having the same shape and hybridization)?

A.$\text{BCl}_3$ and $\text{BrCl}_3$
B.$\text{NH}_3$ and $\text{NO}_3^-$
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D.$\text{BF}_4^-$ and $\text{NH}_4^+$
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Among the following, isoelectronic species are:

A.$CO_{2}, NO_{2}$
B.$NO_{2}^{-}, CO_{2}$
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C.$\text{CN}^-$, $\text{NO}^+$
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In a regular octahedral molecule, $MX_{6}$, the number of $X–M–X$ bonds at 180º is:

A.Two
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Which orbital does the additional electron occupy when $O_{2}$ is converted to the $O_{2}^{-}$ ion?

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A species that does not exhibit paramagnetism is:

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A.4
B.8
C.12
D.16
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