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NEET CHEMISTRYSome Basic Concepts of ChemistryMedium

Question

What fraction of Fe exists as Fe(III) in Fe0.96OFe_{0.96}O? (Consider Fe0.96Fe_{0.96} to be made up of Fe(II) and Fe(III) only)

A

1/12

B

0.08

C

1/16

D

1/20

Step-by-Step Solution

  1. Establish Charge Neutrality: The compound Fe0.96OFe_{0.96}O is neutral. The oxide ion (O2O^{2-}) has a charge of 2-2. Therefore, the total positive charge contributed by 0.960.96 moles of Iron atoms must be +2+2.
  2. Set up Equations:
  • Let the fraction of Fe3+Fe^{3+} be xx and the fraction of Fe2+Fe^{2+} be (1x)(1-x).
  • Alternatively, consider 100 formula units of Fe0.96OFe_{0.96}O contains 96 Fe atoms and 100 O atoms.
  • Total charge of Fe atoms = Total charge of O atoms = 200200.
  • Let number of Fe3+Fe^{3+} be aa and Fe2+Fe^{2+} be bb.
  • Eq 1 (Atom balance): a+b=96a + b = 96
  • Eq 2 (Charge balance): 3a+2b=2003a + 2b = 200
  1. Solve for 'a' (Fe3+Fe^{3+}):
  • From Eq 1, b=96ab = 96 - a.
  • Substitute into Eq 2: 3a+2(96a)=2003a + 2(96 - a) = 200
  • 3a+1922a=2003a + 192 - 2a = 200
  • a=8a = 8
  1. Calculate Fraction:
  • The number of Fe(III)Fe(III) ions is 8.
  • The total number of Fe ions is 96.
  • Fraction = 896=112\frac{8}{96} = \frac{1}{12}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Some Basic Concepts of Chemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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